Number Theory
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Number of Divisors

Count of divisors from prime factorization exponents.

Formula

d(n)=∏(ai+1)d(n) = \prod (a_i + 1)

Variables

a_iPrime exponents

Example

12=2²·3: (2+1)(1+1)=6

How it works

If an integer is written as a product of primes, each prime factor can appear in a divisor with any exponent from 0 up to its exponent in the original number. That gives a separate set of choices for each prime, and the total number of divisors is the product of the number of choices for each exponent. The factor (a_i + 1) appears because an exponent a_i allows exactly a_i + 1 possibilities: 0, 1, 2, ..., a_i.

When to use it

Use this when you know the prime factorization of a positive integer and want to count how many divisors it has without listing them all. It is especially useful in divisor-counting problems, number theory proofs, and questions about highly composite numbers.

Worked example, step by step

Find the number of divisors of 360. 360 = 2^3 · 3^2 · 5^1 The exponents are 3, 2, and 1. d(360) = (3 + 1)(2 + 1)(1 + 1) d(360) = 4 · 3 · 2 d(360) = 24 So, 360 has 24 positive divisors.

Common mistakes to avoid

  • Forgetting to include exponent 0, which makes each factor count as a_i + 1 rather than a_i
  • Using the prime values themselves instead of their exponents in the product
  • Applying the formula to a number before factoring it into primes completely

Did You Know?

The number of divisors comes straight from the prime factorisation, a neat trick of exponents plus one.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026