Number Theory
Basic

Sum of First n Integers

Closed form for the sum of the first n natural numbers.

Formula

∑k=1nk=n(n+1)2\sum_{k=1}^{n} k = \frac{n(n+1)}{2}

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Variables

nUpper limit

Example

1 + 2 + … + 100 = 100·101/2 = 5050 (as young Gauss famously found).

How it works

This formula gives the total when you add the counting numbers from 1 up to n without writing them all out. It works because the list can be paired from the ends: 1 with n, 2 with n-1, and so on, and each pair has the same sum, n+1. There are n/2 such pairs, so the total is n(n+1)/2.

When to use it

Use this when you need the sum of a consecutive run of whole numbers, such as counting objects in rows, finding the total of the first n terms of a simple counting pattern, or checking arithmetic-series sums quickly. It is especially useful in combinatorics, number theory, and mental math.

Worked example, step by step

Find 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 Use the formula: n(n+1)/2 Substitute n = 8: 8(8+1)/2 Simplify: 8·9/2 Compute: 72/2 = 36 So, 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36

Common mistakes to avoid

  • Using n instead of n+1 in the formula
  • Forgetting that the formula applies to consecutive integers starting at 1
  • Multiplying by n/2 incorrectly when n is odd without understanding that the final formula still gives an integer

Did You Know?

Gauss allegedly found this formula as a schoolboy to sum 1 through 100 in seconds.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026