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Lorentz Factor

Scaling factor in special relativity.

Formula

γ=11−v2/c2\gamma = \frac{1}{\sqrt{1 - v^2/c^2}}

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Variables

vSpeed
cLight speed

How it works

The Lorentz factor tells you how strongly space and time measurements change when something moves at speed v relative to an observer. It appears because Einstein’s special relativity keeps the speed of light fixed for all inertial observers, so time intervals, lengths, and momentum cannot transform in the simple Newtonian way. As v gets close to c, the denominator shrinks and \gamma grows rapidly, which is why relativistic effects become dramatic near light speed.

When to use it

Use this formula whenever you need relativistic corrections for time dilation, length contraction, relativistic momentum, or kinetic energy. It is especially important in particle physics, astrophysics, and any problem where speeds are a significant fraction of the speed of light.

Worked example, step by step

A muon in a particle beam moves at v = 0.80c. Step 1: Write the formula: \gamma = 1 / \sqrt{1 - v^2/c^2} Step 2: Substitute v/c = 0.80: \gamma = 1 / \sqrt{1 - (0.80)^2} Step 3: Square the speed ratio: (0.80)^2 = 0.64 Step 4: Compute the denominator: \sqrt{1 - 0.64} = \sqrt{0.36} = 0.60 Step 5: Divide: \gamma = 1 / 0.60 = 1.67 Final answer: \gamma \approx 1.67, so relativistic effects are 1.67 times stronger than in the muon’s rest frame for quantities scaled by \gamma.

Common mistakes to avoid

  • Using v instead of the ratio v/c, which makes the expression dimensionally wrong
  • Forgetting that the square applies to the speed ratio, not just the speed
  • Using this formula for speeds equal to or greater than c, where it is not physically valid

Did You Know?

The Lorentz factor stays near 1 in daily life, so relativity's weirdness only shows at enormous speeds.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026