Linear Algebra
Advanced

Eigenvalue Equation

Defines eigenvalues and eigenvectors of a matrix.

Formula

Av⃗=λv⃗A\vec{v} = \lambda\vec{v}

Variables

AMatrix
\vec{v}Eigenvector
\lambdaEigenvalue

Example

For A = [[2,0],[0,3]], v = (1,0) is an eigenvector with eigenvalue λ = 2.

How it works

The equation A\vec{v} = \lambda\vec{v} says that after a matrix acts on a nonzero vector, the vector does not change direction: it is only stretched, shrunk, or reversed. That special vector \vec{v} is an eigenvector, and the scaling factor \lambda is its eigenvalue. It works because we are looking for vectors that lie on a one-dimensional invariant subspace of the linear transformation, so the transformation acts like multiplication by a scalar along that direction.

When to use it

Use this when you want to find directions that a linear transformation preserves, such as principal axes in geometry, normal modes in vibrations, or steady-state behavior in dynamical systems. It is also central in diagonalization, stability analysis, PCA, and solving differential equations with linear systems.

Worked example, step by step

Take A = [[4,1],[0,2]]. Let \vec{v} = (1,0). Compute A\vec{v} = [[4,1],[0,2]](1,0) = (4,0). Now compare (4,0) with \lambda(1,0). We need \lambda(1,0) = (4,0), so \lambda = 4. Therefore, \vec{v} = (1,0) is an eigenvector of A with eigenvalue \lambda = 4. Check: A\vec{v} = (4,0) = 4(1,0) = \lambda\vec{v}.

Common mistakes to avoid

  • Forgetting that the eigenvector must be nonzero
  • Assuming every vector is an eigenvector instead of only special directions
  • Mixing up the eigenvalue equation with the characteristic equation det(A - \lambda I) = 0

Did You Know?

Eigenvectors are the special directions a matrix merely stretches — the math behind Google's original PageRank.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026