Geometry & Trigonometry
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Inradius

Radius of a triangle inscribed circle.

Formula

r=Ksr = \frac{K}{s}

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Variables

KArea
sSemi-perimeter

Example

Largest circle that fits inside

How it works

The inradius r is the distance from the center of a triangle’s incircle to any side, so the incircle touches all three sides without crossing them. The key idea is that a triangle’s area can be split into three smaller triangles, each with height r and bases equal to the side lengths, which gives K = rs where s is the semiperimeter. Rearranging that area relationship yields r = K/s.

When to use it

Use this when you know a triangle’s area and its side lengths, or when you can find the semiperimeter from the sides. It is especially useful in geometry proofs, optimization problems, and any problem involving an incircle or tangent lengths.

Worked example, step by step

Find the inradius of a triangle with sides 13 cm, 14 cm, and 15 cm. Step 1: Find the semiperimeter. s = (13 + 14 + 15) / 2 = 42 / 2 = 21 cm Step 2: Find the area using Heron's formula. K = √[s(s-a)(s-b)(s-c)] = √[21(21-13)(21-14)(21-15)] K = √[21 × 8 × 7 × 6] = √7056 = 84 cm² Step 3: Apply the inradius formula. r = K / s = 84 / 21 = 4 cm Final answer: the inradius is 4 cm.

Common mistakes to avoid

  • Using the full perimeter instead of the semiperimeter s
  • Forgetting that K must be the triangle’s area, not a side length or height
  • Mixing up the inradius with the circumradius, which is the radius of the circle through the vertices

Did You Know?

A triangle's inradius equals its area divided by its semiperimeter — the radius of the largest circle that fits inside.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026