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Second Moment of Area (Rect.)

Resistance of a rectangular section to bending.

Formula

I=bh312I = \frac{bh^3}{12}

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Variables

bWidth
hHeight

Example

A beam 0.1 m wide, 0.2 m deep: I = 0.1·0.2³/12 ≈ 6.7×10⁻⁵ m⁴.

How it works

The second moment of area measures how the shape of a cross-section is distributed about a bending axis, and for a rectangle it increases very strongly with height because the outer fibers carry most of the bending effect. The factor h^3 appears because material farther from the neutral axis contributes disproportionately to resisting bending, while the width b contributes linearly since widening the section adds material evenly across the span. This result comes from integrating y^2 across the rectangular area about its centroidal axis, which is why the units are length to the fourth power.

When to use it

Use this formula when you need the bending stiffness of a rectangular cross-section in beam design, stress analysis, or deflection calculations. It is also useful for comparing design changes, such as whether increasing depth or width gives a bigger gain in stiffness.

Worked example, step by step

A rectangular timber beam has width b = 75 mm and height h = 180 mm. I = bh^3 / 12 I = 75 × 180^3 / 12 mm^4 180^3 = 5,832,000 I = 75 × 5,832,000 / 12 I = 437,400,000 / 12 I = 36,450,000 mm^4 So, I = 3.645 × 10^7 mm^4 = 3.645 × 10^-5 m^4.

Common mistakes to avoid

  • Using the wrong dimension for h: the height is the dimension perpendicular to the bending axis, and it is the one that gets cubed
  • Forgetting that the formula gives the centroidal second moment of area, not the polar moment of area
  • Mixing units, such as entering dimensions in mm but expecting the answer in m^4 without converting

Did You Know?

An I-beam puts material far from the center because bending resistance grows with the cube of depth.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026