Bending Stress
Stress in a beam due to bending.
Formula
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Example
Deeper beams resist bending far better — stress falls as the section gets taller.
How it works
This equation gives the normal stress at a specific point in a beam cross-section when the beam is bent. It comes from the idea that, under pure bending, cross-sections stay plane, so fibres farther from the neutral axis stretch or compress more; the stress varies linearly with distance y and is larger when the bending moment M is larger. The moment of area I measures how strongly the cross-section resists that bending, so a larger I spreads the stress out and reduces the peak value.
When to use it
Use this for beams, shafts, and structural members when you need the bending stress at a particular location in the cross-section. It is especially useful in design checks, failure analysis, and comparing how changing a section shape affects stress.
Worked example, step by step
Given: bending moment M = 18 kN·m, distance from neutral axis y = 60 mm, second moment of area I = 8.0 × 10^6 mm^4 Step 1: Convert the moment to consistent units. 18 kN·m = 18 × 10^6 N·mm Step 2: Substitute into σ = My / I. σ = (18 × 10^6 N·mm × 60 mm) / (8.0 × 10^6 mm^4) Step 3: Calculate. σ = 135 N/mm^2 Step 4: State the result. σ = 135 MPa So the bending stress at that point in the beam is 135 MPa.
Common mistakes to avoid
- Mixing units, such as using N·m with mm^4 without converting consistently
- Using the overall beam depth instead of the point’s distance y from the neutral axis
- Confusing the second moment of area I with mass moment of inertia
Did You Know?
Bending stress is highest at a beam's outer surface — which is why cracks start there.
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