Electronics & Circuits
Intermediate

Voltage Divider

Output voltage from two series resistors.

Formula

Vout=VinR2R1+R2V_{out} = V_{in}\frac{R_2}{R_1 + R_2}

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Variables

V_{in}Input voltage
R_1,R_2Resistors

How it works

A voltage divider uses two resistors in series to split an input voltage into a smaller output voltage across one of the resistors. Because the same current flows through both resistors in a series circuit, the voltage across each resistor is proportional to its resistance, so the output across R_2 is the input voltage multiplied by the fraction R_2 / (R_1 + R_2). This comes directly from Ohm’s law and the fact that series resistances add.

When to use it

Use this when you need to create a lower reference voltage from a higher supply, such as feeding an analog input, setting a bias voltage, or scaling a signal for a sensor or microcontroller. It is also useful any time two resistors are used in series and you want the voltage at their midpoint.

Worked example, step by step

Given: V_in = 12 V, R_1 = 3 kΩ, R_2 = 9 kΩ Step 1: Add the resistors in series: R_1 + R_2 = 3 kΩ + 9 kΩ = 12 kΩ Step 2: Substitute into the formula: V_out = V_in × R_2 / (R_1 + R_2) Step 3: V_out = 12 × 9 / 12 Step 4: V_out = 9 V Final answer: The output voltage across R_2 is 9 V.

Common mistakes to avoid

  • Using the wrong resistor in the numerator, which gives the voltage across the other resistor instead
  • Forgetting that the resistors must be in series for this formula to apply
  • Ignoring load current on the output, which can change the divider voltage in real circuits

Did You Know?

The humble voltage divider, just two resistors, is one of the most-used circuits in all of electronics.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026