Capacitive Reactance
Opposition of a capacitor to AC.
Formula
Variables
How it works
A capacitor does not resist steady DC current in the usual way; instead, it limits AC current because the voltage across it must continually change as charge builds up and collapses on its plates. The formula X_C = 1/(2\pi f C) shows that this opposition gets smaller when the signal frequency increases or when the capacitance is larger, because the capacitor can charge and discharge more easily during each cycle. It comes directly from the sinusoidal relation between current and voltage in a capacitor, where current leads voltage and the effective impedance magnitude is inversely proportional to angular frequency.
When to use it
Use this when analyzing AC circuits containing capacitors, such as filters, coupling networks, timing circuits, or impedance calculations in audio and RF systems. It is especially useful when you need to compare how a capacitor behaves at different frequencies.
Worked example, step by step
Given: f = 1.5 kHz = 1500 Hz, C = 220 nF = 220 \times 10^-9 F Step 1: Write the formula X_C = 1 / (2\pi f C) Step 2: Substitute the values X_C = 1 / (2\pi \times 1500 \times 220 \times 10^-9) Step 3: Calculate the denominator 2\pi \times 1500 \times 220 \times 10^-9 \approx 0.002073 Step 4: Invert X_C \approx 1 / 0.002073 \approx 482.4 \Omega Final answer: X_C \approx 482 \Omega
Common mistakes to avoid
- Using capacitance in microfarads or nanofarads without converting to farads first
- Forgetting that reactance depends on frequency, so the same capacitor has different X_C values at different frequencies
- Confusing capacitive reactance with resistance and treating it as a power-dissipating quantity
Did You Know?
A capacitor blocks steady current but passes rapidly changing signals, the basis of audio tone controls.
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