Electronics & Circuits
Intermediate

Capacitor Energy

Energy stored in a capacitor.

Formula

E=12CV2E = \tfrac{1}{2}CV^2

Variables

CCapacitance
VVoltage

How it works

This formula gives the electrical potential energy a capacitor stores when it has charge separated across its plates. It comes from the work needed to move charge onto the capacitor: as more charge builds up, the voltage rises, so the average voltage during charging is half the final voltage, which leads to the factor of 1/2. The stored energy depends on both how much charge the capacitor can hold (capacitance) and how high the voltage is, with voltage having a particularly strong effect because the energy scales with V^2.

When to use it

Use this when you need to find how much energy is stored in a capacitor in a circuit, such as in flash units, power backup circuits, timing circuits, or energy-storage calculations. It is also useful when comparing different capacitor-voltage combinations to see which stores more energy.

Worked example, step by step

A capacitor of 220 \u03bcF is charged to 12 V. Step 1: Convert capacitance to farads: C = 220 \u03bcF = 220 \u00d7 10^-6 F = 2.20 \u00d7 10^-4 F Step 2: Substitute into E = 1/2 CV^2 E = 1/2 \u00d7 (2.20 \u00d7 10^-4) \u00d7 (12)^2 Step 3: Square the voltage: 12^2 = 144 E = 0.5 \u00d7 2.20 \u00d7 10^-4 \u00d7 144 Step 4: Multiply the numbers E = 1.584 \u00d7 10^-2 J Final answer: E \u2248 0.0158 J, or 15.8 mJ

Common mistakes to avoid

  • Using capacitance in microfarads without converting to farads
  • Forgetting to square the voltage term
  • Mixing up capacitor energy with power, which is measured in watts rather than joules

Did You Know?

A camera flash dumps a capacitor's stored energy in milliseconds, producing a burst far brighter than its battery could.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026