Chemistry
Intermediate

Combustion of a Hydrocarbon

Complete combustion of a hydrocarbon in oxygen, releasing energy and producing carbon dioxide and water.

Formula

CxHy+(x+y4)O2→x CO2+y2 H2OC_xH_y + \left(x + \tfrac{y}{4}\right)O_2 \rightarrow x\,CO_2 + \tfrac{y}{2}\,H_2O

Variables

CₓHᵧHydrocarbon fuel
xCarbon atoms
yHydrogen atoms
O₂Oxygen

Example

Methane: CH₄ + 2O₂ → CO₂ + 2H₂O

How it works

This equation shows the complete combustion of a hydrocarbon, meaning every carbon atom ends up as carbon dioxide and every pair of hydrogen atoms ends up as water. The coefficients come from balancing atoms: x carbons require x CO2 molecules, y hydrogens require y/2 H2O molecules, and the oxygen needed is then counted from the products, giving x + y/4 O2 molecules. It only applies when oxygen is plentiful enough for complete burning, so no carbon monoxide or soot is formed.

When to use it

Use this formula when balancing reactions for fuels such as alkanes, or when calculating how much oxygen is needed for full combustion. It is also useful for finding the amounts of CO2 and H2O produced from burning a known hydrocarbon sample.

Worked example, step by step

Example: complete combustion of propane, C3H8 Step 1: Identify x and y. C3H8 means x = 3 and y = 8. Step 2: Find the oxygen coefficient. x + y/4 = 3 + 8/4 = 3 + 2 = 5 Step 3: Write the balanced equation. C3H8 + 5O2 → 3CO2 + 4H2O Step 4: Check atoms. Left: C = 3, H = 8, O = 10 Right: C = 3, H = 8, O = 10 So the equation is balanced.

Common mistakes to avoid

  • Forgetting that oxygen must be balanced after carbon and hydrogen are matched
  • Using the wrong water coefficient and writing y H2O instead of y/2 H2O
  • Applying the formula to incomplete combustion, where CO or soot may form instead of only CO2 and H2O

Did You Know?

Incomplete combustion (too little oxygen) produces carbon monoxide and soot instead of clean CO₂ and water.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026