Aviation & Aeronautics
Intermediate

Power Required (Level Flight)

Power needed to sustain level flight equals drag times true airspeed.

Formula

Pr=D×VP_r = D \times V

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Variables

P_rPower required
DDrag
VTrue airspeed

Example

Drag 2000 N at 100 m/s: P_r = 200 kW

How it works

In steady level flight, an aircraft is not accelerating up, down, or along its path, so the engine only needs to supply enough power to balance the aerodynamic drag. Since power is the rate of doing work and work against drag equals force times distance, multiplying drag by true airspeed gives the rate at which energy must be delivered to the airflow. This is why higher drag or higher speed both increase the required power.

When to use it

Use this when analyzing an aircraft in steady, level cruise or any situation where lift balances weight and thrust balances drag. It is especially useful for estimating engine power demand, comparing cruise speeds, or finding how changes in drag affect fuel use.

Worked example, step by step

Given: Drag D = 1500 N, True airspeed V = 80 m/s Step 1: Write the formula: P_r = D × V Step 2: Substitute the values: P_r = 1500 × 80 Step 3: Calculate: P_r = 120000 W Step 4: Convert to kilowatts: P_r = 120 kW Answer: The power required is 120 kW.

Common mistakes to avoid

  • Using indicated airspeed instead of true airspeed
  • Forgetting to convert the answer from watts to kilowatts when needed
  • Applying the formula to climbing or accelerating flight without accounting for extra power requirements

Did You Know?

Power required rises with the cube of speed for parasite drag — flying fast is expensive.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026