Power Required (Level Flight)
Power needed to sustain level flight equals drag times true airspeed.
Formula
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Example
Drag 2000 N at 100 m/s: P_r = 200 kW
How it works
In steady level flight, an aircraft is not accelerating up, down, or along its path, so the engine only needs to supply enough power to balance the aerodynamic drag. Since power is the rate of doing work and work against drag equals force times distance, multiplying drag by true airspeed gives the rate at which energy must be delivered to the airflow. This is why higher drag or higher speed both increase the required power.
When to use it
Use this when analyzing an aircraft in steady, level cruise or any situation where lift balances weight and thrust balances drag. It is especially useful for estimating engine power demand, comparing cruise speeds, or finding how changes in drag affect fuel use.
Worked example, step by step
Given: Drag D = 1500 N, True airspeed V = 80 m/s Step 1: Write the formula: P_r = D × V Step 2: Substitute the values: P_r = 1500 × 80 Step 3: Calculate: P_r = 120000 W Step 4: Convert to kilowatts: P_r = 120 kW Answer: The power required is 120 kW.
Common mistakes to avoid
- Using indicated airspeed instead of true airspeed
- Forgetting to convert the answer from watts to kilowatts when needed
- Applying the formula to climbing or accelerating flight without accounting for extra power requirements
Did You Know?
Power required rises with the cube of speed for parasite drag — flying fast is expensive.
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