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Landing Ground Roll

Approximate landing roll distance from touchdown speed and average deceleration.

Formula

s=Vtd22as = \dfrac{V_{td}^2}{2a}

Variables

sGround roll distance
V_{td}Touchdown speed
aAverage deceleration

Example

Vtd 60 m/s, a = 3 m/s²: s = 3600/6 = 600 m

How it works

This formula estimates how far an aircraft will travel along the runway after touchdown before it comes to a stop, assuming its deceleration is roughly constant. It comes from the constant-acceleration kinematics relation v^2 = u^2 + 2as, applied with final speed v = 0 and initial speed u = Vtd, then rearranged to solve for distance. Because it uses the average deceleration, it is a simplified model that captures the main effect of braking, drag, and reverse thrust without tracking each one separately.

When to use it

Use this when you need a quick estimate of landing distance during runway planning, performance analysis, or safety margin checks. It is especially useful in problems that give touchdown speed and an average braking/deceleration value rather than detailed time-varying forces.

Worked example, step by step

Touchdown speed: Vtd = 55 m/s Average deceleration: a = 2.75 m/s² Use s = Vtd² / (2a) s = 55² / (2 × 2.75) s = 3025 / 5.5 s = 550 m Final answer: the landing ground roll is approximately 550 m.

Common mistakes to avoid

  • Using cruise speed or approach speed instead of touchdown speed
  • Forgetting that the deceleration goes in the denominator, so stronger braking means a shorter roll
  • Mixing up units, such as using km/h for speed and m/s² for deceleration without converting

Did You Know?

Landing distance scales with the square of touchdown speed — 10% faster means 21% more runway.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026