Vehicle Speed from RPM
Road speed from engine rpm, gearing and tyre diameter.
Formula
Variables
Example
Lower rpm at a given speed means taller gearing and better economy.
How it works
This formula converts engine speed into road speed by chaining together two ideas: the gearbox and final drive reduce the engine’s rpm before it reaches the wheels, and the tyres turn wheel rotations into distance travelled. The tyre circumference is c0d, so each wheel revolution moves the vehicle forward by that distance; multiplying by wheel revs per minute and converting through the gear ratios gives road speed. It works best when the tyre diameter is the effective rolling diameter, not just the nominal tyre size printed on the sidewall.
When to use it
Use this when estimating how fast a vehicle should travel at a given engine rpm in a chosen gear, or when comparing gearing changes such as different differential ratios or tyre sizes. It is also useful for diagnosing speedometer error or checking whether a vehicle’s gearing suits cruising, towing, or acceleration.
Worked example, step by step
Given: tyre diameter d = 0.65 m, engine speed N = 3000 rpm, gear ratio GR = 1.20, final drive G_f = 3.90 Step 1: Multiply gear ratio and final drive: GR d7 G_f = 1.20 d7 3.90 = 4.68 Step 2: Calculate tyre circumference: c0d = c0 d7 0.65 = 2.042 m Step 3: Find road speed: v = (c0dN) / (GR d7 G_f) = (2.042 d7 3000) / 4.68 = 1309.0 m/min Step 4: Convert to km/h: 1309.0 d7 60 / 1000 = 78.5 km/h Final answer: the vehicle speed is about 78.5 km/h at 3000 rpm in that gear.
Common mistakes to avoid
- Using tyre diameter in inches without converting it to metres or consistent units
- Forgetting that gear ratio and final drive both reduce wheel speed, so both must be included
- Using the nominal tyre size instead of the actual rolling diameter, which can shift the result noticeably
Did You Know?
Tall final-drive ratios let motorway cars cruise at 120 km/h while the engine barely ticks over.
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