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Apparent Brightness

Observed flux from a source at distance d.

Formula

b=L4πd2b = \frac{L}{4\pi d^2}

Variables

LLuminosity
dDistance

Example

Inverse-square dimming

How it works

This formula gives the brightness per unit area that an observer measures from a source emitting luminosity L when that energy spreads out uniformly through space. As the light travels outward, it is distributed over the surface of a sphere with area 4c0d^2, so the same total power is diluted over a larger area as distance increases. That geometric spreading is why apparent brightness falls off with the inverse square of distance.

When to use it

Use this when converting an object's intrinsic power output into the flux received at Earth or by a detector, such as for stars, supernovae, or other radiating sources. It is especially useful in distance estimation, comparing sources at different distances, and connecting luminosity to observational data.

Worked example, step by step

A star has luminosity L = 5.0 10^27 W and is located at d = 2.0 10^15 m from Earth. Step 1: Write the formula: b = L / (4c0d^2) Step 2: Square the distance: d^2 = (2.0 10^15 m)^2 = 4.0 10^30 m^2 Step 3: Compute the denominator: 4c0d^2 = 4c0(4.0 10^30)  5.03 10^31 m^2 Step 4: Divide: b = (5.0 10^27 W) / (5.03 10^31 m^2)  9.95 10^-5 W/m^2 Final answer: b  1.0 10^-4 W/m^2

Common mistakes to avoid

  • Using d instead of d^2, which misses the inverse-square dependence
  • Forgetting the 4c0 factor from the surface area of a sphere
  • Mixing units, such as using distance in parsecs without converting consistently when L is in watts

Did You Know?

Starlight dims with the inverse square of distance, so a star twice as far appears four times fainter.

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Reviewed & maintained by the FormulaWon editorial teamLast reviewed September 2026